Android : Send data ang image in a httpurlconnection

I konw this has been asked a couple of times in this site but I could not find a correct way to do it.

I want to upload a file from android to server using HTTPURLCONNECTION and PHP. I found tutorial on it but only in sending the file not with data. data includes file name, details/description and comments.

FileInputStream fileInputStream = new FileInputStream(sourceFile);
               URL url = new URL(upLoadServerUri);

               // Open a HTTP  connection to  the URL
               conn = (HttpURLConnection) url.openConnection(); 
               conn.setDoInput(true); // Allow Inputs
               conn.setDoOutput(true); // Allow Outputs
               conn.setUseCaches(false); // Don't use a Cached Copy
               conn.setRequestMethod("POST");
               conn.setRequestProperty("Connection", "Keep-Alive");
               conn.setRequestProperty("ENCTYPE", "multipart/form-data");
               conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
               conn.setRequestProperty("uploaded_file", fileName);
               conn.setRequestProperty("Filename","testfilename");


               JSONObject cred = new JSONObject();
               cred.put("name","juan");
               cred.put("password","pass");

               dos = new DataOutputStream(conn.getOutputStream());


               // for every param
               dos.writeBytes("Content-Disposition: form-data; name=\"chunk\"" + lineEnd);
               dos.writeBytes("Content-Type: text/plain; charset=UTF-8" + lineEnd);
               dos.writeBytes("Content-Length: " + cred.length() + lineEnd);
               dos.writeBytes(lineEnd);
               dos.writeBytes(cred.toString() + lineEnd);
               dos.writeBytes(twoHyphens + boundary + lineEnd);

               /**Create file*/
               dos.writeBytes(twoHyphens + boundary + lineEnd);
               dos.writeBytes (cred.toString());
               dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\""
                                         + fileName + "\"" + lineEnd);
               dos.writeBytes(lineEnd); //close the streams //
               fileInputStream.close();
               dos.flush();
               dos.close();

and in my php :

 $name=$this->input->post('name');

  $headers = $this->input->request_headers();
  // print_r('sample result: - '.$headers['Filename']);
  $file_name = $headers['Filename'];
  $config2['upload_path'] = 'cms/uploads/reports_images/';
  $config2['allowed_types'] = 'jpg|png|xls';
  $config2['max_size'] = '2048';
  $config2['file_name'] = $file_name.'_'.date('Y_m_d_H_i_s',time());
  $this->load->library('upload',$config2);
  $this->upload->initialize($config2);

  echo "name ".'-'.$name;  
  // $file_path = $file_path . basename( $_FILES['uploaded_file']['file_name']);
  if($this->upload->do_upload('uploaded_file')) {
      echo "success".'-'.$name;
  } else{
      echo "fail";
      print_r($this->upload->display_errors());
  }

but tried to print the response in the log cat and this is what i got

HTTP Response is : name -fail

You did not select a file to upload.

How should it be done correctly?

Thanks for your help.