Android : Android open an external Navigation app

I'd like to make an option in my app so the user can open his navigation app in order to navigate to a specific lat,lng coordinates.

After some reading I realized there's no standard URI for navigation, so I can't just do:

private Activity thisActivity;

public void navigate(double destLat, double destLng){
    String uri = "geo: "+ destLat + "," + destLng;
    Intent intent = new Intent(android.content.Intent.ACTION_VIEW,
            Uri.parse(uri));
    if(isAppExists(intent))
        thisActivity.startActivity(intent);

}

public boolean isAppExists(Intent intent){
    PackageManager packageManager = thisActivity.getPackageManager();
    List<ResolveInfo> activities = packageManager.queryIntentActivities(intent, 0);
    boolean isIntentSafe = activities.size() > 0;
    return isIntentSafe;
}

Since by doing this, the app chooser also opens Google Maps (which doesn't support this URI format, for example).

My question is, before implementing a custom dialog to choose only between navigation apps that I support (by writing a special URI for each one of them: for waze using the geo: query, and for google maps, its own format), is there any other way making it with the default app chooser?

Please note that I don't think createChooser method would help me since I can only prevent the selection AFTER the user has selected it, but it would look really bad.

So in the bottom line, what I need to do is to remove apps that I do not support from the app chooser. Do I really have to implement my own custom dialog?

Thanks