Android : Adding 2 queries from 2 php files together

I'm working on an android app where i'm supposed to create one recipe including it's picture. I have one php file called create_recipe.php, in that file i'm creating the title ingredients, description and category, all these values are created in a single query. Also, I have a second php file called UploadImage.php to pick a photo from the gallery or from camera and upload it to the web server, and this is done in a single query as well. In my java code i'm calling create_recipe.php first and then UploadImage.php. Doing it like this will make the information to be saved in a deferent rows

I tried several thing to make it one query so that all the information are together: 1- Merging the files to be one file, and only making one query the result was: every thing was added but not the image, because UploadImage.php wasn't called yet. 2- Saving the value of image and add it to the create_recipe.php, didn't work again because UploadImage.php wasn't called yet. 3-Since create_recipe.php is called before UploadImage.php and i know that there is an id for each recipe with auto increment value, I tried to call it by mysqli_insert_id ( ) and then update the rows with the image but again that didn't work.

My question is is there any way to make this query in a single row in the DB ? Any help would be greatly appreciated!

Here is my code for UploadImage.php

<?php


$target_path    =   "./images".basename( $_FILES['uploadedfile']['name']);
$pic            =   ($_FILES['photo']['name']); 
$file_path      =   $_FILES['tmp_name'];

// include db connect class
define('__ROOT__', dirname(dirname(__FILE__)));
require_once(__ROOT__.'/android_connect/db_connect.php');

// connecting to db
$db = new DB_CONNECT();




if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
    echo "The file ".  basename( $_FILES['uploadedfile']['name'])." has been uploaded";
    // Make your database insert only if successful and insert $target_path, not $file_path
    // Use mysqli_ or PDO with prepared statements
   $result =   mysql_query("INSERT INTO scb( name) VALUES('$target_path')");// here i'm making the query to add the image



    }
else
  echo "There was an error uploading the file, please try again!";



?>;

Here is my code for create_recipe.php

<?php


/*
 * Following code will create a new recipe row
 * All recipe details are read from HTTP Post Request
 */

// array for JSON response
$response = array();

 // check for required fields
if (isset($_POST['title']) && isset($_POST['ingredients']) && isset($_POST['description'])&&     isset($_POST['category']) ) {
//  && isset($_POST['image'])

$title = $_POST['title'];
 $ingredients = $_POST['ingredients'];
 $description = $_POST['description'];
 $category = $_POST['category'];


 // include db connect class
 define('__ROOT__', dirname(dirname(__FILE__)));
 require_once(__ROOT__.'/android_connect/db_connect.php');

// connecting to db
$db = new DB_CONNECT();

// mysql inserting a new row
$result = mysql_query("INSERT INTO scb(title, ingredients, description, category, name)     VALUES('$title', '$ingredients', '$description', '$category', '$target_path')");// 


    // check if row inserted or not
    if ($result) {
    // successfully inserted into database
    $response["success"] = 1;
    $response["message"] = "Recipe successfully created.";

     // echoing JSON response
    echo json_encode($response);
   } else {
    // failed to insert row
    $response["success"] = 0;
    $response["message"] = "Oops! An error occurred.";

    // echoing JSON response
    echo json_encode($response);
    }
    } else {
    // required field is missing
   $response["success"] = 0;
   $response["message"] = "Required field(s) is missing";

   // echoing JSON response
   echo json_encode($response);

}